If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4z^2-16z-9=0
a = 4; b = -16; c = -9;
Δ = b2-4ac
Δ = -162-4·4·(-9)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-20}{2*4}=\frac{-4}{8} =-1/2 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+20}{2*4}=\frac{36}{8} =4+1/2 $
| 9x-8=8x-12 | | -7y+5=-2 | | 3x^-18=0 | | 11(5x)=58 | | x-(2x-1)=105 | | 4(w+18)=16 | | 2p+17+2p-21+5p-67=180 | | 8300+0.04s=1750+0.08s | | 7x=4x+9=180 | | -4m-8m+14=50 | | 107+4x+7=180 | | 2(2y+25)=8y-17=180 | | 2(2y+25)=8y-17 | | 5(2x)+2+2x+2+x+2=58 | | 2(2y+25)=8y–17 | | 600=300+0.04s | | 8x-2-5)=x+25 | | 2/3m=38 | | -1/2x+6=-8 | | x^-36=-9-2x^ | | 5x+24=7x+9 | | 8300=1750+0.04s | | 1750=0.04s | | m–2/3=1/3 | | m– 23= 13 | | -4|2/3x-6|+5=11 | | 25/x=10/150 | | 4x+17+39=2x+2 | | 2x^-400=0 | | (x+3)/3=10+4/4 | | 18x+5+57=29x+7 | | 8=4-2(c-2) |